Помогитееееее!!!!!!!срочнооооо!!!!!!!!!!!!!

Question

Помогитееееее!!!!!!!срочнооооо!!!!!!!!!!!!!

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Answer 1

Решение
log₃¹/² (1/9√3) = 2*log₃¹/² [3⁻⁵/²]¹/² = 2*log₃¹/² (3¹/²)⁻⁵/² = 
= 2*(-5/2) *log₃¹/² (3¹/²) = - 5