Решить одно уравнение Х+1+√(х+1)=6
√(x + 1) = 6 - x - 1 √( x + 1) = 5 - x x + 1 = ( 5 - x)² x + 1 = ( 5 - x)( 5 - x) x + 1 = 25 - 10x + x² - x² + 11x - 24 = 0 x² - 11x + 24 = 0 D = b² - 4ac = 121 - 4 × 24 = 121 - 96 = 25 = 5² x1 = ( 11 + 5) / 2 = 8 x2 = ( 11 - 5) / 2 = 3