(x^2+3x)(x^2+3x-3)=4

Question

(x^2+3x)(x^2+3x-3)=4

Answer 1

X² + 3x = 4
x² + 3x - 4 = 0
D = b² - 4ac = 3² - 4 × 1 × (-4) = 9 + 16 = 25 = 5²
x1 = ( - 3 + 5) / 2 = 1
x2 = ( - 3 - 5) / 2 = - 4

x² + 3x - 3 = 4
x² + 3x - 7 = 0
D = b² - 4ac = 3² - 4 × 1 × ( - 7) = 9 + 28 = 37
x1,2 = - 3+/-√37/2