Система уравнения: ху-х=24 и х-3у=-5

$\left \{ {{xy-x=24} \atop {x-3y=-5}} \right.$

$\left \{ {{x(y-1)=24} \atop {x=3y-5}} \right. \\ \\ \left \{ {{(3y-5)(y-1)=24} \atop {x=3y-5}} \right. \\ \\ \left \{ {{3y^2-8y-19=0} \atop {x=3y-5}} \right. \\ \\ \left \{ {{3y^2-8y-19=0} \atop {x=3y-5}} \right.$

Решаем первое уравнение
3y²-8y-19=0
D=64-4·3·(-19)=4·(16+57)=4·73
y=(8-2√73)/6=(4-√73)/3 или у=(8+2√73)/6=(4+√73)/3
х=3у-5=-1-√73 х=-1+√73

Ответ. (-1-√73; (4-√73)/3) (-1+√73; (4+√73)/3)