{log√2 (x+y)=2 {3^x*7^x=21

Question

{log√2 (x+y)=2 {3^x*7^x=21

Answer 1

Log_√2 (x + y) = 2
(3^x) * (7^x) = 21

(3^x) * (7^x) = 21
(21)^x = 21
x = 1

x = 1
log_√2 (1 + y) = 2

x = 1
1 + y = (√2)²

x = 1
y = 2 - 1

x = 1
y = 1

Ответ:  (1;1)