4^x-2^2(x-1)+8^2/3(x-2)>52 (2*(x-1) и 2/3(x-2) - это показатели)

Решите задачу:

$4^{x} - 2^{2(x-1)}+ 8^{ \frac{2}{3}(x-2)} \ \textgreater \ 52 \\ \\ 2^{2x} - \frac{2^{2x}}{4} +(2^{3})^{ \frac{2x}{3}- \frac{4}{3} } \ \textgreater \ 52 \\ \\ \frac{3}{4} * 2^{2x} + \frac{1}{16} * 2^{2x} \ \textgreater \ 52 \\ \\ \frac{13}{16} * 2^{2x} \ \textgreater \ 52 \\ \\ 2^{2x} \ \textgreater \ \frac{52*16}{13} \\ \\ 2^{2x} \ \textgreater \ 2^{6} \\ \\ 2x\ \textgreater \ 6 \\ \\ x\ \textgreater \ 3$