Решите плиз систему: x^2+y^2=5 x-y=b

Question

Решите плиз систему:
x^2+y^2=5
x-y=b

Answer 1

X^2-2*x*y+y^2+2*x*y=5
x-y=b
(x-y)^2+2*x*y=5
x-y=b
b^2+2*x*y=5
x*y=(5-b^2)/2
x-y=b bu yerden hem x-i tapyp yerine bahasyny goyyarys
x=b+y
y*(b+y)-(5-b^2)/2=0
y^2+y*b-(5-b^2)/2=0
2y^2+2y*b-5+b^2=0
D=(2b)^2-4*2*(b^2-5)=4*b^2-8*b^2+40=40-4*b^2=4(10-b^2)
 mundan son bahalaryny yerine goyup alyp bolar