Решите систему уравнений

$\left \{ {{x=2+y} \atop {3x-2y=9}} \right. \left \{ {{x=2+y} \atop {3(2+y)-2y=9} \right. \left \{ {{x=2+y} \atop {y=3}} \right. \left \{ {{x=5} \atop {y=3}}$
Ответ: $(5;3)$
$\left \{ {{5x+y=4} \atop {x=3+2y}} \right. \left \{ {{5(3+2y)+y=4} \atop {x=3+2y}} \right. \left \{ {{15+11y=4} \atop {x=3+2y}} \right \left \{ {{11y=-11} \atop {x=3+2y}} \right. \left \{ {{y=-1} \atop {x=1}} \right.$
Ответ: $(1;-1)$