Решить системы 2 И 3 ИСПОЛЬЗУЯ ФОТО ИЛИ СТРОКУ ФОРМУЛ

Решите задачу:

$\left \{ {{5^{x+2y}=1} \atop {lg(x-3)=lg(2y+5)}} \right. \; ;\; \; ODZ:\; \left \{ {{x\ \textgreater \ 3} \atop {y\ \textgreater \ -\frac{5}{2}}} \right. \\\\ \left \{ {{x+2y=0} \atop {x-3=2y+5}} \right. \; \left \{ {{x+2y=0} \atop {x-2y=8}} \right. \; \left \{ {{x=-2y} \atop {2x=8}} \right. \; \left \{ {{y=-2} \atop {x=4}} \right. \\\\Otvet:\; (4,-2).$

$3)\; \left \{ {{log_3x+log_3y=1} \atop {y-3x=8}} \right. \; \; ODZ:\; x\ \textgreater \ 0,\; y\ \textgreater \ 0\\\\ \left \{ {{xy=3} \atop {y=3x+8}} \right. \; \left \{ {{3x^2+8x-3=0} \atop {y=3x+8}} \right. \; \left \{ {{x_1=-3,\; x_2=\frac{1}{3}} \atop {y_1=-1,\; y_2=9}} \right. \\\\Otvet:\; (\frac{1}{3};9).$