y=4x²-3x+1 y` -? y= cosx+sinx y` -? ʄ(x) = x2 * ( x +3 )2

Question

y=4x²-3x+1

y` -?

y= cosx+sinx

y` -?

ʄ(x) = x2 * ( x +3 )2

Answer 1

1) 8x-3

2) cosx-sinx

3) 2*x*(x-3)*(2x-3)