Sin(π+α)+cos(3/2π-α)+tg(π+α)

Question

Sin(π+α)+cos(3/2π-α)+tg(π+α)

Answer 1

Sin(π+α)=-sin x cos(3/2π-α)=-sin x tg(π+α)=tgx -sinx -sinx+tgx=-2sinx+tgx