1
( x +1 ) (x - 2) (2x + 5) ≥0
x=-1 x=2 x=-2,5
_ + _ +
--------[-2,56]-----------[-1]---------[2]---------------
x∈[-2,5;-1] U [2;∞)
2
(x-4)/(x+5)>0
x=4 x=-5
+ _ +
-------------(-5)--------------(4)-----------------
x∈(-∞;-5) U (4;∞)
3
px^2+(2p-3)x+(p+3)>0
{p>0
{D<0<br>D=(2p-3)²-4p(p+3)=4p²-12p+9-4p²-12p=-24p+9<0<br>24p>9
p>3/8
p∈(3/8;∞)