Как решать систему уравнений 2-3x=2(1-y) и 4(x+y)=x-1.5

$\left \{ {{2-3x=2(1-y)} \atop {4(x+y)=x-1.5}} \right.$

$\left \{ {{2-3x=2-2y} \atop {4x+4y=x-1.5}} \right.$

$\left \{ {{-3x=-2y} \atop {3x+4y=-1.5}} \right.$

$\left \{ {{-3x+2y=0} \atop {3x+4y=-1.5}} \right.$

$\left \{ {{6y=-1.5} \atop {3x+4y=-1.5}} \right.$

$\left \{ {{y=-1.5:6} \atop {3x+4y=-1.5}} \right.$

$\left \{ {{y=-0.25} \atop {3x+4*(-0.25)=-1.5}} \right.$

$\left \{ {{y=-0.25} \atop {3x-1=-1.5}} \right.$

$\left \{ {{y=-0.25} \atop {3x=-0.5}} \right.$

$\left \{ {{y=-0.25} \atop {x=-0.5:3}} \right.$

$\left \{ {{y=-0.25} \atop {x=- \frac{1}{6} }} \right.$

Ответ: $(- \frac{1}{6};-0.25)$