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$1)5 \frac{4}{27}+3 \frac{5}{18}=8+ \frac{8}{54}+ \frac{15}{54}=8 \frac{23}{54} \\ \\ 2)5 \frac{1}{3}-2 \frac{1}{4} =3+ \frac{4}{12}- \frac{3}{12}=3 \frac{1}{12} \\ \\ 3)10 \frac{3}{4}-7 \frac{5}{6}=3+ \frac{9}{12}- \frac{10}{12}=3- \frac{1}{12}=2 \frac{11}{12} \\ \\ 4) \frac{3}{10}- \frac{2}{15}+ \frac{7}{12}=\frac{18}{60}- \frac{8}{60}+ \frac{35}{60}= \frac{45}{60}= \frac{3}{4}$