60 баллов!!!!! Решите уравнение (2целых 2/3x+1целая 3/7x)*21=58!!!!
(2 2/3 х +1 3/7 х)*21=58 (2 14/21 х + 1 9/21 х)* 21=58 (3 23/21 х)*21=58 4 2/21 х*21=58 86/21 х * 21=58 86х=58 х=58/86 х=29/43
( 2 ( 2/3 )Х + 1 ( 3/7)Х ) * 21 = 58 2 ( 2/3)X + 1 ( 3/7 )X = 58 : 21 2 ( 14/21 )X + 1 ( 9/21 )X = 58/21 ( 56/21 )X + ( 30/21 )X = 58/21 56X + 30X = 58 86X = 58 X = 58/86 X = 29/43