Сколько существует таких натуральных n от 1 до 99, что [100/(n+1)] = [100/n]?

Найдем, для каких чисел это равенство НЕ выполняется.
1) n = 1. [100/2] = 50 =/= [100/1] = 100
2) n = 2. [100/3] = 33 =/= [100/2] = 50
3) n = 3. [100/4] = 25 =/= [100/3] = 33
4) n = 4. [100/5] = 20 =/= [100/4] = 25
5) n = 5. [100/6] = 16 =/= [100/5] = 20
6) n = 6. [100/7] = 14 =/= [100/6] = 16
7) n = 7. [100/8] = 12 =/= [100/7] = 14
8) n = 8. [100/9] = 11 =/= [100/8] = 12
9) n = 9. [100/10] = 10 =/= [100/9] = 11
10) n = 10. [100/11] = 9 =/= [100/10] = 10
11) n = 11. [100/12] = 8 =/= [100/11] = 9
12) n = 12. [100/13] = 7 =/= [100/12] = 8
13) n = 14. [100/15] = 6 =/= [100/14] = 7
14) n = 16. [100/17] = 5 =/= [100/16] = 6
15) n = 20. [100/21] = 4 =/= [100/20] = 5
16) n = 25. [100/26] = 3 =/= [100/25] = 4
17) n = 33. [100/34] = 2 =/= [100/33] = 3
18) n = 50. [100/51] = 1 =/= [100/50] = 2
Для остальных 100 - 18 = 82 чисел равенство выполняется.