СРОЧНО СРОЧНО СРОЧНО!!!!!!! помогите ребята срочно нужно исправить оценки 409,412,413

409)
$1)~-4,35\ \textless \ 4,3 \\ 2)~-8 \frac{1}{4} \ \textless \ -7 \frac{3}{4} \\ 3)~6,81\ \textgreater \ -6,9$

$4)~- \frac{7}{15} \ \textgreater \ - \frac{5}{9} \\ \\ ~~~~- \frac{21}{45} ~\ \textgreater \ -\frac{25}{45}$

$5)~- \frac{5}{13}\ \textless \ - \frac{2}{13} \\ 6)~0,9\ \textgreater \ -1$

412)
$1) ~-5\ \textless \ x\ \textless \ +30\\ 2)~+10\ \textless \ x\ \textless \ +44 \\ 3)~+10\ \textless \ x\ \textless \ +37$

413)
$1)~|-7|-|-3,6|:|1,2|=7-3,6:1,2=7-3=4 \\ \\ 2)~|6 \frac{3}{7} |:|-9|+4 \frac{1}{3} =6 \frac{3}{7}:9+4 \frac{1}{3} = \frac{45}{7} : \frac{9}{1} +4 \frac{1}{3} = \frac{45*1}{~7*9} +4 \frac{1}{3} = \\ = \frac{5}{7} + \frac{13}{3} = \frac{15+91}{21} = \frac{106}{21} =5 \frac{1}{21}$

$3)~|- \frac{7}{24} |\cdot|-1 \frac{1}{7} |\cdot3=\frac{7}{24}\cdot1 \frac{1}{7}\cdot3= \frac{7}{24}\cdot \frac{8}{7} \cdot \frac{3}{1} = \frac{~7\cdot8\cdot3}{24\cdot7} =1 \\ \\ 4)~|-2,7|:|-1 \frac{4}{5} |\cdot|1 \frac{5}{9}|= 2,7:1 \frac{4}{5} \cdot1 \frac{5}{9} = \frac{27}{10} : \frac{9}{5} \cdot \frac{14}{9} = \frac{27\cdot5\cdot14}{10\cdot9\cdot9} = \frac{21}{9} = \\= \frac{7}{3} =2 \frac{1}{3}$