Log₂ (x + 1) + log₂ (x + 3) = 3
Решаем логарифмическое уравнение
Log ₂ ( X + 1 ) + log ₂ ( X + 3 ) = 3 log ₂ ( X + 1 )*( X + 3 ) = 3 2 ^ 3 = ( X + 1 )*( X + 3 ) X² + 4X + 3 - 8 = 0 X²+ 4X - 5 = 0 D = 16 + 20 = 36 ; √ D = 6 X1 = ( - 4 + 6 ) : 2 = 1 X2 = ( - 4 - 6 ) : 2 = - 5