Решите уравнение: 1)84а+25а+7=443 2)4(9+7х)+21=393

Question

Решите уравнение:
1)84а+25а+7=443
2)4(9+7х)+21=393

Comments

1)84а+25а+7=443 2)4(9+7х)+21=393109а+7=443 36+28х+21=393109а=443-7 28х+57=393109а=436 28х=393-57а=436:109 28х=336а=4 х=336:28 х=12

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1)84а+25а+7=443 2)4(9+7х)+21=393109а+7=443 36+28х+21=393109а=443-7 28х+57=393109а=436 28х=393-57а=436:109 28х=336а=4 х=336:28 х=12

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Понял

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Answer 1

109a = 443 - 7
109a = 436
a = 436/109
a = 4

36 + 28x + 21 =393
28x = 393 - 57
28x = 336
x = 336/28
x = 12

Answer 2

1)  84а + 25а + 7 = 443        2) 4(9+7х) + 21 = 393

109а = 443 - 7                          36 + 28х + 21 = 393
109а = 436                               28х + 57 = 393
а = 4                                         28х = 393 - 57

                                                  28х = 336
                                                     х = 12