Помогите с 3 номером

Question

Помогите с 3 номером

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Answer 1

А)
(4x²-4х-3)/(2х+1)-(4х²-9)/(2х+3)=
(4х²-4х-3)/(2х+1)-(2х-3)(2х+3)/(2х+3)=[(4х²-4х-3)-(2х-3)(2х+1)]/(2х+1)=(4х²-4х-3-4х²-2х+6х+3)/(2х+1)=0
б)
(х³-х²-16х+16)/( х²+3х-4)=
[х²(х-1)-16(х-1)]/(х²+3х-4)=
[(х²-16)(х-1)]/(х²+3х-4)