Помогите пожл сократить дробь 3у^2+2y-1/5у+5
(3у²+2y-1)/(5у+5)=3(y-1/3)(y+1)/5(y+1)=3(y-1/3)/5=(3y-1)/5 3у²+2y-1=0 D=4+12=16 x₁=(-2+4)/6=1/3 x₂=(-2-4)/6=-1