1)(1/125)^4x=5 2)2*3^x+1-6*3^x-1-3^x=9

Question

1)(1/125)^4x=5
2)2*3^x+1-6*3^x-1-3^x=9

Answer 1

3^(x - 1)(2·3² - 6 - 3) = 9
3^(x -1) ·9 = 9
3^(x - 1) = 1
3^(x -1) = 3^0
x -1 = 0
x = 1