Решение
(X+1)(x+2)(x+3)(x+4)=3
[(X+1)(x+4)]*[(x+2)(x+3)] = 3
(x² + 5x + 4)*(x² + 5x + 6) = 3
Gecnm x² + 5x + 4 =t
t*(t + 2) = 3
t² + 2t - 3 = 0
t1 = - 3
t2 = 1
x² + 5x + 4 = - 3
x² + 5x + 7 = 0
D = 25 - 4*1*7 = - 3 < 0
решений нет
x² + 5x + 4 = 1
x² + 5x + 3 = 0
D = 25 - 4*1*3 = 13
x1 = (- 5 -√13) /2 = - √13 / 2 - 2(1/2)
x2 = (- 5 + √13) /2 = √13 / 2 - 2(1/2)