1/3х+1/4х+1/8х=34/45 4 2/15-3 1/9х=1 4/5

Решите задачу:

$\frac{8+6+3}{24}x= \frac{34}{45} \\ \frac{17}{24} x= \frac{34}{45} \\ x=\frac{34}{45}* \frac{24}{17} \\ x= \frac{48}{45} \\ x=1 \frac{1}{15} \\ \\ \\ 3 \frac{1}{9}x= 4 \frac{2}{15} -1 \frac{4}{5} \\ 3 \frac{1}{9} x= \frac{62}{15} - \frac{9}{5} \\ \frac{28}{9}x= \frac{62-27}{15} \\ \frac{28}{9}x= \frac{35}{15} \\ x= \frac{35}{15} * \frac{9}{28} \\ x= \frac{15}{20}= \frac{3}{4}$