2 sin 60 + 3 sin 45 +10 cos60 -4 cos45- tg60

Question

2 sin 60 + 3 sin 45 +10 cos60 -4 cos45- tg60

Answer 1

2 sin 60 + 3 sin 45 +10 cos60 -4 cos45- tg60=2*√3/2+3*√2/2+10*1/2-4*√2/2-√3= √3+1,5√2+5-2√2-√3=5-√2/2