sin8xcos2x= sin7xcos3x помогите, УМОЛЯЮ !!!
Sin8xcos2x-sin7xcos3x=1/2(sin10x+sin6x-sin10x-sin4x)= =1/2(sin6x-sin4x)=sinxcos5x=0 sinx=0 x=Пk, k∈Z cos5x=0 5x=П/2+Пn x=П/10+Пn/5