4cos³x-3cosx=0
cosx(4cos²x-3)=0
cosx=0⇒x=π/2+πn,n∈Z
4cos²x=3
2(1+cos2x)=3
1+cos2x=1,5
cos2x=0,5
2x=+-π/3+2πk,k∈Z
x=+-π/6+πk,k∈Z
1)-2π≤π/2+πn≤-π
-4≤1+2n≤-2
-5≤2n≤-3
-2,5≤n≤-1,5
n=-2⇒x=π/2-2n=-3π/2
2)-2π≤-π/6+πk≤-π
-12≤-1+6k≤-6
-11≤6k≤-5
-11/6≤k≤-5/6
k=-1⇒x=-π/6-π=-7π/6
3)-2π≤π/6+πk≤-π
-12≤1+6k≤-6
-13≤6k≤-7
-13/6≤k≤-7/6
k=-2⇒x=π/6-2π=-11π/6