19/84:(5целых13/42-2целых13/28+5/24)+1целая2/27-1/3х4/9=?(с решениями)

Решите задачу:

$\frac{19}{84}:\left(5\frac{13}{42}-2\frac{13}{28}+\frac5{24}\right)+1\frac2{27}-\frac13\cdot\frac49=\\ =\frac{19}{84}:\left(\frac{223}{42}-\frac{69}{28}+\frac5{24}\right)+\frac{29}{27}-\frac4{27}=\\ =\frac{19}{84}:\left(\frac{892-414+35}{168}\right)+\frac{25}{27}=\\ =\frac{19}{84}:\frac{513}{168}+\frac{25}{27}=\frac{19}{84}\cdot\frac{168}{513}+\frac{25}{27}=\frac2{27}+\frac{25}{27}=\frac{27}{27}=1$