Решите и получите 50 баллов!!

Решите задачу:

$\log_\frac{1}{2}(7x-1)=-3, \\ \left \{ {{7x-1\ \textgreater \ 0,} \atop {7x-1=(\frac{1}{2})^{-3};}} \right. \left \{ {{x\ \textgreater \ \frac{1}{7},} \atop {7x-1=8;}} \right. \left \{ {{x\ \textgreater \ \frac{1}{7},} \atop {7x=9;}} \right. \left \{ {{x\ \textgreater \ \frac{1}{7},} \atop {x=1\frac{2}{7};}} \right. \\ x=1\frac{2}{7};$

$\log_4(5-6x)=2,\\ \left \{ {{5-6x\ \textgreater \ 0,} \atop {5-6x=4^2;}} \right. \left \{ {{ x\ \textless \ \frac{5}{6},} \atop {5-6x=16;}} \right. \left \{ {{ x\ \textless \ \frac{5}{6},} \atop {6x=-11;}} \right. \left \{ {{ x\ \textless \ \frac{5}{6},} \atop {=-1\frac{5}{6};}} \right. \\ x=-1\frac{5}{6};$

$\log_416+\log_749-\log_327=\log_44^2+\log_77^2-\log_33^3=\\=2\log_44+2\log_77-3\log_33=2+2-3=1.$