Решить уравнение,помогите)
4^(4-x)=1/16 4^(4-x)=(1/4)² 4^(4-x)=4⁻² 4-x=-2 x=6 (1/5)^(2-4x)=∛5 (1/5)^(2-4x)=5¹/³ (1/5)^(2-4x)=(1/5)⁻¹/³ 2-4x=-1/3 -4x=-1/3-2 x=(-7/3):(-4) x=7/12
4^(4-х)=1/16 4^(4-х)=4^(-2) 4-х=-2 х=4+2 х=6 (1/5)^(2-4х)=куб!/5 (1/5)^(2-4х)=5^(1/3) (1/5)^(2-4х)=(1/5)^(-1/3) 2-4х=-1/3 4х=2+1/3 4х=2 1/3 х=7/3×1/4 х=7/12 4^(-3х-4)=4 -3х-4=1 -3х=5 х=-5/3=-1 2/3