Помогите пожалуйста решить уравнения
6) 2^x = 32 2^x = 2^5 x=5 5) 2^x =16 2^x =2^4 x = 4 4) 2^(2x) = 2 2^(2x) = 2^1 2x = 1 x = 1/2 1) 3^x = 9^(x+1) 3^x =3^(2(x+1)) x = 2(x+1) x =2x + 2 – x = 2 x = – 2 2) 7^(1–4x) = 1 7^(1–4x) 7^0 1–4x = 0 – 4x = – 1 x = 1/4 3) 3^ (x^2–4x) = 9 3^ (x^2–4x) = 3^2 x^2 – 4x = 2 x^2 – 4x – 2 = 0 D = 16–4*(–2)=16+8=24 √24 = √(4*6) = 2√6 x1 = (4+2√6)/2 = 2+√6 x2 = (4–2√6)/2 = 2–√6
1) 3^x=9^(x+1) 3^x=3^2(x+1) x=2(x+1) x=2x+2 x-2x=2 x=2 2)7^1-4x=1 7^1-4x=7^0 1-4x=0 -4x=0-1 -4x=-1 x=-1/4 3)3^x^2 -4x=9 3^x^2 -4x=3^2 x^2-4x=2 x(x-4)=2 x=2 или x-4=2 x=2+4 x=6 4)2^2x=2 2^2x=2^1 2x=1 x=1/2 5)2^x=16 2^x=2^4 x=4 6)2^x=32 2^x=2^5 x=5
В первом x=2x+2, x-2x=2,-x=2,x=-2