1)
(x+y)(x²-xy+y²)=7
xy(x+y)=-2
(x+y)(x²+2xy+y²-3xy)=7
xy(x+y)=-2
(x+y)((x+y)²-3xy)=7
xy(x+y)=-2
Пусть xy=a
(x+y)=b
b(b²-3a)=7
ab=-2
b³-3ab=7
ab=-2
b³+6=7
ab=-2
b³=1
ab=-2
b=1
a=-2
xy=-2
x+y=1
x(1-x)=-2
y=1-x
-x²+x+2=0
y=1-x
x²-x-2=0
D=1+4=5
x₁=(1-√5)/2 y₁=1-1/2+√5/2=(1+√5)/2
x₂=(1+√5)/2 y₂=1-(1+√5)/2=(1-√5)2