задание во вложений:) Тема:"Метод интегрирования" Найти:

$\int{(3x-8)}\, dx=\int{3x}\, dx - \int{{8}\, dx=\frac{3}{2}x^2 - 8x +C$

$\int{(2+3\sin x)}\, dx=\int{2}\, dx + \int{{3\sin x}\, dx=2x - 3\cos x +C$

$\int{(2x^2-\cos x)}\, dx=\int{2x^2}\, dx - \int{\cos x}\, dx=\frac{2}{3}x^3-\sin x +C$

$\int{(\frac{3}{\sin^2}+\frac{1}{x})}\, dx=\int{\frac{3}{\sin^2}}\, dx + \int{\frac{1}{x}}\, dx=\\ =-3 ctg x + \ln |x| +C$

$\int{(a^x+\frac{3}{1+x^2})}\, dx=\int{a^x}\, dx + \int{\frac{3}{1+x^2}}\, dx=\\ =\frac{a^x}{ln a} + 3\arctan x +C$

$\int{(\frac{4}{\sqrt{1-x^2}}-8x+\frac{4}{x})}\, dx=\\ \int{\frac{4}{\sqrt{1-x^2}}\, dx - \int{8x}\, dx + \int{\frac{4}{x}}\, dx=\\ =4 \arcsin x - 4x^2 + 4 \ln |x| +C$