Решите неравенство: 4х-7 черта дроби 16^x-32 >0
(4x-7)/16(x-√2)(x+√2)>0 x=1,75 x=√2 x=-√2 _ + _ + --------------(-√2)---------------(√2)---------------(1,75)--------------- x∈(-√2;√2) U (1,75;∞)