Log3(3x-1)+log3(1+x)=1+log3(x+3)
Log3((3x-1)*(1+x))=log3 3+ log3 (x+3) log3((3x-1)*(1+x)=log3 (3*(x+3))<=> <=> (3x-1)*(1+x)=3*(x+3) 3x+3x²-1-x=3x+9 3x²-x-10==0 D = 1+120= 121 x1= (1+11/6)= 2 x2=(1-11/6)= 10/6= 5/3 = 1 целая (2/3) ответ: 1 целая 2/3 2