Sin 150° Cos 135° Tg 120°

Question

Sin 150° Cos 135° Tg 120°

Answer 1

Sin150° = sin(180-150)=sin30°=0.5
cos135°=-cos(180-135)=-cos45°=-1/√2
tg120°=sin120°/cos120°=sin(180°-120°)/(-cos(180°-120°)=
= -sin60°/cos60°=-tg60° = -√3