Помогите решить. 5sin(2x-п/12)= -5
Sin(2x -π/12) = -5/5 sin(2x - π/12) = -1 2x - π/12 = -π/2 + 2πk, k∈Z 2x=π/12 -π/2 + 2πk 2x= -5π/12 +2πk x= -5π/24 + πk, k∈Z