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Решите задачу:

$\left \{ {{3sin x -2 cos y=-2} \atop {4cos y - sin x =-1}} \right\\ \left \{ {{3sin x -2 cos y=-2} \atop {4cos y+1= sin x}} \right\\ 3(4cos y +1) -2 cos y=-2\\ 12 cos y+3 -2cos y+2=0\\10 cos y+5=0\\cos y =-\frac{1}{2}$

$y= +- arccos(-\frac{1}{2})+2 \pi n\\ y_{1}= \frac{2\pi}{3}+2\pi n\\ y_{2}=- \frac{2\pi}{3}+2\pi n\\$

$sin x = 4*(-\frac{1}{2})+1=-1\\ x=-\frac{\pi}{2} +2 \pi n$ $\frac{2\pi}{3}*\frac{3\pi}{2}=\pi ^2$