3^x·3 +18/3^x = 29 | ·3^x = t
3t² +18 = 29 t
3 t² - 29 t +18 = 0
D = b²-4ac = 841 - 216 = 625
t1 = (29+25)/6 = 54/6 = 9
t2 = (29 - 25)/6 = 4/6 = 2/3
a) 3^x = 9 б) 3^x = 2/3
x = 2 x lg3 = lg2 - lg3
x = (lg2 - lg3)/lg3
2√x - 3 = 4 |²
4(x - 3) = 16
4x -12 = 16
4x = 28
x = 7