Решение
1) (x+3)(x-4)=-12
x² - x - 12 = - 12
x(x - 1) = 0
x₁ = 0
x₂ = 1
Ответ: х₁ = 0 : х₂ = 1
2) (3x-1)^2=1
3x - 1 = - 1
3x = 0
x₁ = 0
3x - 1 = 1
3x = 2
x₂ = 2/3
Ответ: х₁ = 0; х₂ = 2/3
3) (2x+3)(3x+1)=11x+30
6x² + 11x + 3 = 11x + 30
6x² = 27
x² = 9/2
x₁ = - 3√2/2
x₂ = 3√2/2
Ответ: x₁ = - 3√2/2; x₂ = 3√2/2
4) 18-(x-5)(x-4)=-2
x² - 9x + 20 = 20
x(x - 9) = 0
x₁ = 0
x₂ = 9
Ответ: x₁ = 0 ; x₂ = 9
5) 5x+(2x+1)(x-3)=0
5x + 2x² - 5x - 3 = 0
2x² - 3 = 0
2x² = 3
x² = 3/2
x₁ = - √6/3
x₂ = √6/3
6) x^2-5=(x-5)(2x-1)
x² - 5 = 2x² - 11x + 5
x² - 11x + 10 = 0
x₁ = 1
x₂ = 10
Ответ: x₁ = 1 ; x₂ = 10