Sin=5/13 и 3/2<<2 Найти cos

Question

Sin=5/13 и 3/2<<img src="https://tex.z-dn.net/?f=%5Cbeta+" id="TexFormula3" title="\beta " alt="\beta " align="absmiddle" class="latex-formula"><2<img src="https://tex.z-dn.net/?f=+%5Cpi+" id="TexFormula4" title=" \pi " alt=" \pi " align="absmiddle" class="latex-formula"> Найти cos

Answer 1

Решение
cosβ = √(1 - sin²β) = √(1 - (5/13)²) = √(1 - 25/169) =
= √(144/169) = 12/13