log2 x -log2 3=log 2(2x-5)
I'm assuming everthing in the above question is to log of base 2.
log2 x -log2 3=log2 (2x-5)
Apply logarithm law: log a - log b = log (a/b)
log2 (x/3) = log2 (2x-5)
Remove the log function from both sides of the equation.
x/3 = 2x-5