Решение
1) log₁/₂ (1/4√2) = - log₂ 2⁵/² = 2,5
2) log₆ 2 + log₆ 3 = log₆ (2*3) = 1
3) log₂³/² 512 = (2/3)*log₂ 2⁸ = 16/3
4) log₁/₂ (8b²) = log₁/₂ 8 + log₁/₂ b² = - log₂ 2³ - 2log₂ b =
= - 8 - 2*(log₄ b / log₄ 2) = - 8 - 2*(- 6 / log₄ 2) =
= - 8 + 12 / [(1/2)* log₂² 2²] = - 8 + 24 = 16