Дано: d=4 an=50 Sn=330. найдите a1 и n
An=a1+(n-1)d 50 =a1 +(n-1)*4 a1=54-4n Sn=(a1+an)/2*n 330*2=(a1+50)*n a1=660/n -50 660/n -50 = 54-4n|*n 4n^2-104n+660=0|^4 n^2-26n+165=0 (n-11)(n-15)=0 1)n=11 a1=54-44=10 2) n=15 a1=54-60=-6