1) (1/3)^x-7 = 1/81 2)2^x + 2^x+3 = 9 3) 3^2x - 4*3^x+3=0 4)4x>1/64 5)(1/4)^x<1/16...

Question

1) (1/3)^x-7 = 1/81
2)2^x + 2^x+3 = 9
3) 3^2x - 4*3^x+3=0
4)4x>1/64
5)(1/4)^x<1/16<br> 6)0,5^3-2x + 3* 0,25^1-x = 7
7)2^2x + 4*2^x>=5
9) {27^x=9^y
{81^x = 3^y+1
заранее спасибо

Answer 1

1/9 х - 7 -1/81 = 0.....разделим на 1/9

х - 63 -1/9=0......х= 63+1/9.....х=63 и 1\9