log2x+log корень из 2 х+log1\2 x = 8

Question

log2x+log корень из 2 х+log1\2 x = 8

Answer 1

log2x+2log 2 х-log2 x = 8

 2log 2 х=8

 log 2 х =4

 x=16

 

Answer 2

og2x+2log 2 х-log2 x = 8

 2log 2 х=8

 log 2 х =4

 x=16