№1
а) -(3х+ 10) ≥2-х
-3x-10>=2-x
-3x+x>=10+2
-2x>=12
x<=6</span>
б) х2-(х-4)(х+4)> 2х
x^2-x+4x+4>2x
3x>-4
x>-4/3
в) х-2/6 -х/3≤2
x-x/3<=2/6+2</span>
2/3x<=7/3</span>
x<=7/2</span>
№2
|(х+2)(х-3) ≤х2
|4х+1/7-х/2>0
(x+2)(x-3)<=x^2</p>
x+2x-3<=x^2</p>
-x^2+3x-3=0 |*(-1)
x^2-3x+3=0
D=(-3)^2-4*1*3=9-12=-3 - нет решений
4x+1/7-x/2>0
4x-x/2>-1/7
7/2x>-1/7
x>2/49