Решите (X+1)(x+2)-(x+3)(x+4)=0

Question

Решите
(X+1)(x+2)-(x+3)(x+4)=0

Answer 1

(х+1)(х+2) - (х+3)(х+4)=0
(х²+2х+х+2)- (х²+4х+3х+12)=0
х²+3х+2 - х²-7х-12=0
(х²-х²)+(3х-7х)+(2-12)=0
-4х-10=0
-4х=10
х=- 10/4
х=- 2,5
Проверим: (-2,5+1)(-2,5+2)-(-2,5+3)(-2,5+4)=0
-1,5*(-0,5) - (0,5*1,5)=0
0,75-0,75=0
0=0

Answer 2

(1x × 2x) - (3x × 4x) = 0
2x - 12x = 0
-10x = 0
x = - 10 x