(a¹²)⁸= k*k⁸= (k¹²)¹¹/k⁶⁹= (c⁸)⁹/c³⁰= (a¹²)⁸= (c⁹)⁶*c⁴= (d¹²)⁵*d¹⁵= (k²)⁹*k⁸= (k¹⁴)⁶/k³¹=...

Решите задачу:

$1)(a ^{12} )^8=a ^{96}$
$2)k*k^8=k^9$
$3)(k ^{12} ) ^{11} /k ^{69} =k ^{132} /k ^{69} =k ^{63}$
$4)(c^8)^9/c ^{30} =c ^{72}/c ^{30} =c ^{42}$
$5)(a ^{12} )^8=a ^{96}$
$6)(c^9)^6*c^4=c ^{54} *c^4=c ^{58}$
$7)(d ^{12})^5*d ^{15} =d ^{60} *d ^{15} =d ^{75}$
$8)(k^2)^9*k^8=k ^{18} *k^8=k ^{26}$
$9)(k ^{14} )^6/k ^{31} =k ^{84} /k ^{31}=k ^{53}$
$10)(k-3) ^{12} /(k-3)^5=(k-3)^7$