#7 С помощью формулы куба разности преобразуйте в многочлен: д) (5m - 4s)³ e) (3c - 2t)³...

8)
д)
(4c²-5e²)³=(4c²)³-3*(4c²)²*5e²+3*4c²*(5e²)²-(5e²)³=
=64c⁶-240c⁴e²+300c²e⁴-125e⁶

e)
(mn-3l)³=(mn)³-3*(mn)²*3l+3*mn*(3l)²-(3l)³=
=m³n³-9m²n²l+27mnl²-27l³

ж)
(2f-4m)³=(2f)³-3*(2f)²*4m+3*2f*(4m)²-(4m)³=
=8f³-48f²m+96fm²-64m³

з)
(-4m²-2yz)³=(-4m²)³-3*(-4m²)²*2yz+3*(-4m²)*(2yz)²-(2yz)³=
=-64m³-96m⁴yz-48m²y²z²-8y³z³

9)
a)
$(2x- \frac{1}{2} )^3=(2x)^3-3*(2x)^2* \frac{1}{2}+3*2x*( \frac{1}{2} )^2-( \frac{1}{2} )^3= \\ =8x^3-6x^2+1.5x-0.125$

б)
$( \frac{5v}{8}- \frac{7w}{6} )^3=( \frac{5v}{8} )^3-3*( \frac{5v}{8} )^2* \frac{7w}{6}+3* \frac{5v}{8}*( \frac{7w}{6} )^2-( \frac{7w}{6} )^3= \\ = \frac{125v^3}{512}- \frac{525v^2w}{384}+ \frac{735vw^2}{288}- \frac{343w^3}{216}$

в)
$( \frac{3j}{4}+1 )^3=( \frac{3j}{4} )^3+3*( \frac{3j}{4} )^2*1+3* \frac{3j}{4}*1^2+1^3= \\ = \frac{27j^3}{64}+ \frac{27j^2}{16}+ \frac{9j}{4} +1$

г)
( $( \frac{u}{9}+ \frac{3p}{8} )^3=( \frac{u}{9} )^3+3*( \frac{u}{9} )^2* \frac{3p}{8}+3* \frac{u}{9}*( \frac{3p}{8} )^2+( \frac{3p}{8} )^3= \\ = \frac{u^3}{729}+ \frac{9u^2p}{648}+ \frac{27up^2}{576}+ \frac{37p^3}{512}$ )